Y^2+4Y-480=0

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Solution for Y^2+4Y-480=0 equation:


Simplifying
Y2 + 4Y + -480 = 0

Reorder the terms:
-480 + 4Y + Y2 = 0

Solving
-480 + 4Y + Y2 = 0

Solving for variable 'Y'.

Factor a trinomial.
(-24 + -1Y)(20 + -1Y) = 0

Subproblem 1

Set the factor '(-24 + -1Y)' equal to zero and attempt to solve: Simplifying -24 + -1Y = 0 Solving -24 + -1Y = 0 Move all terms containing Y to the left, all other terms to the right. Add '24' to each side of the equation. -24 + 24 + -1Y = 0 + 24 Combine like terms: -24 + 24 = 0 0 + -1Y = 0 + 24 -1Y = 0 + 24 Combine like terms: 0 + 24 = 24 -1Y = 24 Divide each side by '-1'. Y = -24 Simplifying Y = -24

Subproblem 2

Set the factor '(20 + -1Y)' equal to zero and attempt to solve: Simplifying 20 + -1Y = 0 Solving 20 + -1Y = 0 Move all terms containing Y to the left, all other terms to the right. Add '-20' to each side of the equation. 20 + -20 + -1Y = 0 + -20 Combine like terms: 20 + -20 = 0 0 + -1Y = 0 + -20 -1Y = 0 + -20 Combine like terms: 0 + -20 = -20 -1Y = -20 Divide each side by '-1'. Y = 20 Simplifying Y = 20

Solution

Y = {-24, 20}

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